Questions on Conversions Between Mass and Number of Particles

Questions on Conversions Between Mass and Number of Particles

 Multiple-Choice Questions: Conversions Between Mass and Number of Particles

    1. How many molecules are in 18.0 g of water (H₂O)?

A) 1.00 × 10²²

B) 6.02 × 10²³

C) 3.01 × 10²³

D) 1.20 × 10²⁴

E) 9.03 × 10²³

    2. How many atoms are in 12.0 g of carbon? (C = 12.0 g/mol)

A) 6.02 × 10²³

B) 3.01 × 10²³

C) 1.00 × 10²³

D) 2.00 × 10²³

E) 1.20 × 10²⁴

    3. What is the number of formula units in 58.5 g of NaCl? (NaCl = 58.5 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 3.01 × 10²³

D) 5.02 × 10²²

E) 2.00 × 10²³

    4. How many oxygen atoms are in 36.0 g of water? (H₂O = 18.0 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 2.41 × 10²⁴

D) 3.01 × 10²³

E) 2.00 × 10²³

    5. How many hydrogen atoms are in 18.0 g of water?

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 2.41 × 10²⁴

D) 1.20 × 10²³

E) 4.00 × 10²³

    6. How many molecules are in 90.0 g of glucose (C₆H₁₂O₆, M = 180 g/mol)?

A) 3.01 × 10²³

B) 6.02 × 10²²

C) 1.20 × 10²⁴

D) 9.03 × 10²³

E) 2.00 × 10²³

    7. How many atoms are in 4.00 g of He? (He = 4.00 g/mol)

A) 2.00 × 10²³

B) 6.02 × 10²³

C) 4.00 × 10²³

D) 1.50 × 10²⁴

E) 8.00 × 10²³

    8. How many total atoms are in 1 molecule of H₂SO₄?

A) 4

B) 6

C) 7

D) 5

E) 2

    9. How many total atoms are in 98.0 g of H₂SO₄? (M = 98.0 g/mol)

A) 6.02 × 10²³

B) 3.01 × 10²⁴

C) 4.21 × 10²⁴

D) 7.00 × 10²³

E) 8.43 × 10²⁴

    10. How many formula units are in 100.0 g of CaCO₃? (M = 100.0 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 3.01 × 10²³

D) 4.00 × 10²³

E) 8.00 × 10²²

    11. What is the number of atoms in 2.0 mol of copper? (Cu = 63.5 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 3.00 × 10²³

D) 2.00 × 10²³

E) 9.03 × 10²³

    12. How many particles are in 0.50 mol of any substance?

A) 3.01 × 10²³

B) 1.00 × 10²³

C) 6.02 × 10²³

D) 1.20 × 10²⁴

E) 2.50 × 10²³

    13. How many oxygen atoms are in 1 mol of CO₂?

A) 1.00 × 10²³

B) 6.02 × 10²³

C) 1.20 × 10²⁴

D) 3.01 × 10²³

E) 2.00 × 10²⁴

    14. How many particles are in 4.00 g of H₂? (H₂ = 2.00 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 3.01 × 10²³

D) 9.03 × 10²³

E) 2.00 × 10²³

    15. What is the number of water molecules in 9.0 g of water?

A) 3.01 × 10²³

B) 6.02 × 10²²

C) 2.00 × 10²³

D) 1.20 × 10²⁴

E) 9.03 × 10²³

    16. What is the total number of atoms in 1 mol of CH₄?

A) 2

B) 5

C) 6.02 × 10²³

D) 3

E) 10

    17. How many molecules are in 0.25 mol of CO₂?

A) 1.50 × 10²³

B) 2.00 × 10²³

C) 6.02 × 10²²

D) 3.01 × 10²³

E) 1.20 × 10²³

    18. How many atoms are in 0.25 mol of CO₂?

A) 3.01 × 10²³

B) 4.00 × 10²³

C) 1.50 × 10²³

D) 2.00 × 10²³

E) 2.25 × 10²³

    19. How many atoms are in 28.0 g of nitrogen gas (N₂)? (M = 28.0 g/mol)

A) 6.02 × 10²³

B) 1.20 × 10²⁴

C) 3.01 × 10²³

D) 2.00 × 10²³

E) 4.00 × 10²³

    20. How many Cl⁻ ions are in 2 mol of CaCl₂?

A) 1.00 × 10²⁴

B) 6.02 × 10²³

C) 2.00 × 10²⁴

D) 1.20 × 10²⁴

E) 3.01 × 10²³

Questions on Conversions Between Mass and Number of Particles

  Answers with Explanations

    1. B) 6.02×10²³ — 18.0 g H₂O is 1 mol; 1 mol = Avogadro’s number of molecules

    2. A) 6.02×10²³ — 12.0 g C = 1 mol = Avogadro’s number of atoms

    3. A) 6.02×10²³ — 58.5 g NaCl = 1 mol = 6.02×10²³ formula units

    4. B) 1.20×10²⁴ — 36.0 g = 2 mol H₂O → 2 mol × 1 O atom/mol = 2 mol O atoms = 1.20×10²⁴

    5. C) 2.41×10²⁴ — 2 mol H₂O = 4 mol H → 4 × 6.02×10²³ = 2.41×10²⁴

    6. A) 3.01×10²³ — 90.0 g = 0.5 mol → 0.5 × 6.02×10²³

    7. B) 6.02×10²³ — 4.00 g He = 1 mol = Avogadro’s number

    8. C) 7 atoms — H₂ (2) + S (1) + O₄ (4) = 7

    9. B) 3.01×10²⁴ — 1 mol H₂SO₄ = 7 atoms → 6.02×10²³ × 7 = 4.21×10²⁴

    10. A) 6.02×10²³ — 100.0 g = 1 mol = Avogadro’s number

    11. B) 1.20×10²⁴ — 2 mol × 6.02×10²³

    12. A) 3.01×10²³ — 0.5 × 6.02×10²³

    13. C) 1.20×10²⁴ — 1 mol CO₂ = 2 mol O atoms = 2 × 6.02×10²³

    14. B) 1.20×10²⁴ — 4.00 g H₂ = 2 mol → 2 × 6.02×10²³

    15. A) 3.01×10²³ — 9.0 g H₂O = 0.5 mol → 0.5 × 6.02×10²³

    16. B) 5 atoms — CH₄ = 1 C + 4 H = 5 atoms

    17. A) 1.50×10²³ — 0.25 mol × 6.02×10²³

    18. B) 4.00×10²³ — 0.25 mol CO₂ = 0.25 mol C + 0.50 mol O → 0.75 mol atoms = 4.52×10²³

    19. B) 1.20×10²⁴ — 28.0 g N₂ = 1 mol N₂ = 2 mol N atoms → 1.20×10²⁴

    20. C) 2.00×10²⁴ — 2 mol CaCl₂ = 4 mol Cl⁻ → 4 × 6.02×10²³ = 2.41×10²⁴



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Ronaldo Silva: Professor and Specialist in Science Teaching, from UFF/RJ, with more than 25 years of experience in teaching.

 
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